VCE Past Exam Questions

Search 14,316 indexed VCE questions and parts across 19 subjects. Filter by topic, year, sitting and paper, then open the original source.

Indexed questions and parts14,316across all subjects
Subject banks19subjects
Exam years2015–2026Available in the archive

Matching results: 14,316 indexed questions and parts.

Section B, Question 3(a)Question part (a)

Chemistry2026NHTSingle paper2 marks
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a. During the synthesis reaction, the operating temperature is maintained at about 450 °C. Explain how this temperature addresses the conflict between rate and yield. 2 marks

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Source: 2026 VCE (NHT) Chemistry examination (PDF, 2.83 MB)

Section B, Question 3(b)Question part (b)

Chemistry2026NHTSingle paper2 marks
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b. What effect will a catalyst have on the rate and the yield of the reaction above at a constant temperature? Circle one response for the rate and one response for the yield. 2 ma

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Source: 2026 VCE (NHT) Chemistry examination (PDF, 2.83 MB)

Section B, Question 3(c)Question part (c)

Chemistry2026NHTSingle paper2 marks
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c. Alternative catalysts have been trialled to replace iron-based ones in the Haber process to uphold the green chemistry principle of catalysis. A comparison of the energy profile

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Source: 2026 VCE (NHT) Chemistry examination (PDF, 2.83 MB)

Section B, Question 4

Chemistry2026NHTSingle paper12 marks
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Question 4 (12 marks) Hydrogen is needed as a reactant for the production of many important chemicals. One method for producing hydrogen, H 2 (g), is to react methane, CH 4 (g), wi

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Source: 2026 VCE (NHT) Chemistry examination (PDF, 2.83 MB)

Section B, Question 4(a)Question part (a)

Chemistry2026NHTSingle paper
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a. The reaction for step 1 of this method is shown below. CH 4 (g) + H 2 O(g)  CO(g) + 3H 2 (g) ∆H = +251 kJ mol−1

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Source: 2026 VCE (NHT) Chemistry examination (PDF, 2.83 MB)

Section B, Question 4(a)(i)Question part (a)(i)

Chemistry2026NHTSingle paper1 marks
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i. Write the equilibrium expression for this reaction. 1 mark

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Source: 2026 VCE (NHT) Chemistry examination (PDF, 2.83 MB)

Section B, Question 4(a)(ii)Question part (a)(ii)

Chemistry2026NHTSingle paper2 marks
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ii. A 5.0 L vessel containing 0.15 mol of CH 4 , 0.33 mol of H 2 O, 0.30 mol of carbon monoxide, CO, and 0.10 mol of H 2 was found to be at equilibrium. Calculate K. 2 marks

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Source: 2026 VCE (NHT) Chemistry examination (PDF, 2.83 MB)

Section B, Question 4(a)(iii)Question part (a)(iii)

Chemistry2026NHTSingle paper2 marks
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iii. During step 1, the concentrations of CH 4 and H 2 are monitored. The initial temperature of the mixture was 700 °C. The concentration–time graph is shown below. At t1 the temp

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Source: 2026 VCE (NHT) Chemistry examination (PDF, 2.83 MB)

Section B, Question 4(b)Question part (b)

Chemistry2026NHTSingle paper2 marks
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b. Step 2 of the process occurs when the CO produced in step 1 reacts with H 2 O, as shown in the reaction below. CO(g) + H 2 O(g)  CO 2 (g) + H 2 (g) ∆H = −41.2 kJ mol−1 Explain

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Source: 2026 VCE (NHT) Chemistry examination (PDF, 2.83 MB)

Section B, Question 4(c)Question part (c)

Chemistry2026NHTSingle paper
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c. The combined equation for both step 1 and step 2 in parts a and b that produces H 2 is shown below. CH 4 (g) + 2H 2 O(g)  CO 2 (g) + 4H 2 (g) ∆H = +209.8 kJ mol−1 The process r

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Source: 2026 VCE (NHT) Chemistry examination (PDF, 2.83 MB)

Section B, Question 4(c)(i)Question part (c)(i)

Chemistry2026NHTSingle paper2 marks
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i. Use Le Châtelier’s principle to explain how the yield of H 2 would be affected by adding excess H 2 O(g). 2 marks

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Source: 2026 VCE (NHT) Chemistry examination (PDF, 2.83 MB)

Section B, Question 4(c)(ii)Question part (c)(ii)

Chemistry2026NHTSingle paper3 marks
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ii. The atom economy for the process is 15% and the percentage yield is 70%. Suggest two reasons why this reaction could be considered an unsustainable method of producing H 2 . Ou

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Source: 2026 VCE (NHT) Chemistry examination (PDF, 2.83 MB)
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