VCE Mathematical Methods Past Exam Questions
Browse VCE Mathematical Methods exam questions from 2015–2026, including NHT and VCE papers. Filter by topic, year and paper; open the original source.
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Question 9(b)(ii)Question part (b)(ii)
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ii. Determine the nature of this stationary point. 2 marks
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c. Find all values of x such that f (x) ≥ 0. 1 mark
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d. Given that f x dx p q ( ) 0, where p ≠ q and p q R , ∈ , find an expression for p in terms of q. 3 marks
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Question 1 In a random sample of 300 builders, 230 had completed an apprenticeship in the last 10 years. Using this sample, an approximate 95% confidence interval for the populatio
Search excerpt only. Open the original question for exact equations and diagrams.Source: 2026 VCE (NHT) Mathematical Methods examination 2 (PDF, 1.3 MB)Section A, Question 2
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Question 2 Two dice are rolled at the same time. The algorithm below generates the sample space. for i from 1 to 6 for j from 1 to 6 print i, j end for The first printed output is
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Question 3 Assume that the time, in minutes, it takes for a particular student to travel to school is a normal random variable with mean 15 and variance 4. Let Z be a standard norm
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Question 4 The function f D R f x x : , ( ) 4 2 has range (-2, 1]. The domain D is A. [- 4, -1) B. (- 4, -1] C. (-1, 4] D. [-1, 4)
Search excerpt only. Open the original question for exact equations and diagrams.Source: 2026 VCE (NHT) Mathematical Methods examination 2 (PDF, 1.3 MB)Section A, Question 5
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Question 5 Newton’s method can be applied to find an approximate solution to e-x - 2 = 0. If the initial value is x0 = a, where a is a real number, then the value of x1 is A. 2e a
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Question 6 The graph of y = 2x - 1 + 3 is reflected in the line y = x. The rule for the image is A. y = log 2 (2x - 6) B. y = log 2 (2x - 3) C. y = log 2 (3 - x) + 1 D. y = log 2 (
Search excerpt only. Open the original question for exact equations and diagrams.Source: 2026 VCE (NHT) Mathematical Methods examination 2 (PDF, 1.3 MB)Section A, Question 7
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Question 7 Consider the continuous functions f : [0, 2] → R and g : [0, 2] → R, whose graphs are drawn to scale below. x y 1 −1 1 2 y = f (x) y = g (x) O There is a value of x for
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Question 8 The following sequence of steps is an attempt to solve the exponential equation 3 4 3 x . The sequence of steps contains at least one error. Step 1 Take a logarithm of b
Search excerpt only. Open the original question for exact equations and diagrams.Source: 2026 VCE (NHT) Mathematical Methods examination 2 (PDF, 1.3 MB)Section A, Question 9
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Question 9 A straight line is tangent to the graphs of both y = x2 + 4x and y = (x + 5)2 - 4. The gradient of this line is A. - 4 B. 0 C. 4 D. 5
Search excerpt only. Open the original question for exact equations and diagrams.Source: 2026 VCE (NHT) Mathematical Methods examination 2 (PDF, 1.3 MB)How to use ClassConnect past exam questions
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