VCE Mathematical Methods Past Exam Questions
Browse VCE Mathematical Methods exam questions from 2015–2026, including NHT and VCE papers. Filter by topic, year and paper; open the original source.
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Section B, Question 1(d)Question part (d)
d. Find the average value of g between x = 0 and x = 2. 2 marks
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d. Find the equations of the tangent lines to the graph of y = g (x) that have a gradient of 2. 2 marks
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e. Let h be the result after applying a sequence of transformations to g, such that h has a stationary point of inflection at (1, 0) and a local maximum at (-1, 1). Write down a po
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e. Describe a sequence of two transformations that maps the graph of y = g (x) to the graph of y= g (1 — x) 2 marks o ° =) S H FE he Id I ® 2 £ 8 = [=]
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f. Let X p ~ ( , ) Bi 4 be a binomial random variable. Show that Pr ( ) ( ) X g p 3 for all p ∈ [ , ] 0 1 . 2 marks
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f. Leta and b be positive real numbers, such that the graph of y= a x g (x) + b has a local minimum on the x- Express b in terms of a. 1 mark
Search excerpt only. Open the original question for exact equations and diagrams.Source: 2025 VCE (NHT) Mathematical Methods examination 2 (PDF, 4.82 MB)Section B, Question 1(g)Question part (g)
g. For cach real number £, let g; be the function g,: R — R, g(x) = (+ = K)(x +k).
Search excerpt only. Open the original question for exact equations and diagrams.Source: 2025 VCE (NHT) Mathematical Methods examination 2 (PDF, 4.82 MB)Section B, Question 1(g)(i)Question part (g)(i)
i. Find all values of & for which the graph of y = g (x) has exactly one x-intercept. 1 mark
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ii. Find all values of k for which the graph of y = g, (x) has exactly one stationary point. 3 marks, Section B
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Question 2 (12 marks) Consider the function f': D — R, f(x) = 4¢*%™"), where D is the maximal domain of f.
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Question 2 (14 marks) Let f R R f x x : , ( ) 2 7 and g R R g x Ae kx : , ( ) where A k R , ∈ . The graphs of y f x = ( ) and y g x = ( ) intersect at the points (-12, 1) and (2, 8
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a. Write down two simultaneous equations in terms of A and k. Solve them, using algebra, to show that A = 2 18 7 and k e = 3 14 2 log ( ). 3 marks Section B
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