VCE Chemistry Past Exam Questions
Browse VCE Chemistry exam questions from 2015–2026, including NHT and VCE papers. Filter by topic, year and paper; open the original source.
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Section B, Question 3
Question 3 (6 marks) The Haber process for the synthesis of ammonia gas, NH 3 , is considered one of the most important chemical processes of the last 120 years. The process curren
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a. During the synthesis reaction, the operating temperature is maintained at about 450 °C. Explain how this temperature addresses the conflict between rate and yield. 2 marks
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b. What effect will a catalyst have on the rate and the yield of the reaction above at a constant temperature? Circle one response for the rate and one response for the yield. 2 ma
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c. Alternative catalysts have been trialled to replace iron-based ones in the Haber process to uphold the green chemistry principle of catalysis. A comparison of the energy profile
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Question 4 (12 marks) Hydrogen is needed as a reactant for the production of many important chemicals. One method for producing hydrogen, H 2 (g), is to react methane, CH 4 (g), wi
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a. The reaction for step 1 of this method is shown below. CH 4 (g) + H 2 O(g) CO(g) + 3H 2 (g) ∆H = +251 kJ mol−1
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i. Write the equilibrium expression for this reaction. 1 mark
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ii. A 5.0 L vessel containing 0.15 mol of CH 4 , 0.33 mol of H 2 O, 0.30 mol of carbon monoxide, CO, and 0.10 mol of H 2 was found to be at equilibrium. Calculate K. 2 marks
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iii. During step 1, the concentrations of CH 4 and H 2 are monitored. The initial temperature of the mixture was 700 °C. The concentration–time graph is shown below. At t1 the temp
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b. Step 2 of the process occurs when the CO produced in step 1 reacts with H 2 O, as shown in the reaction below. CO(g) + H 2 O(g) CO 2 (g) + H 2 (g) ∆H = −41.2 kJ mol−1 Explain
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c. The combined equation for both step 1 and step 2 in parts a and b that produces H 2 is shown below. CH 4 (g) + 2H 2 O(g) CO 2 (g) + 4H 2 (g) ∆H = +209.8 kJ mol−1 The process r
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i. Use Le Châtelier’s principle to explain how the yield of H 2 would be affected by adding excess H 2 O(g). 2 marks
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